9×261×16×8/(125×10-5)=2405.376Mbit/s
根據(jù)PCM30/32路系統(tǒng)幀結(jié)構(gòu),試求: (1)幀長度; (2)路時(shí)隙tc; (3)位時(shí)隙tB; (4)數(shù)碼率fB。